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-rw-r--r--lessons/matematika/1-exponents/1-id.md77
-rw-r--r--lessons/matematika/1-exponents/1.md41
-rw-r--r--lessons/matematika/1-exponents/2-id.md177
-rw-r--r--lessons/matematika/1-exponents/2.md176
-rw-r--r--lessons/matematika/1-exponents/3-id.json0
-rw-r--r--lessons/matematika/1-exponents/3.json24
6 files changed, 476 insertions, 19 deletions
diff --git a/lessons/matematika/1-exponents/1-id.md b/lessons/matematika/1-exponents/1-id.md
index d791bd0..05a5d69 100644
--- a/lessons/matematika/1-exponents/1-id.md
+++ b/lessons/matematika/1-exponents/1-id.md
@@ -1,19 +1,74 @@
# Pangkat
\\( x^n = x_1 \times x_2 \times\ \cdot\cdot\cdot\ \times x_n \\)
-!---(
-#--(
-## 💡 Loh, kenapa?
-)--#
-
-Ini **harus** menjadi bagian vital dari website ini.
-Menurutku, masalah utama di kurikulum Indonesia ialah kurangnya penjelasan MENGAPA, hanya APA.
-
-)---!
-
## Contoh
* \\(2^5 = 2 \times 2 \times 2 \times 2 \times 2 = 32 \\)
* \\(5^7 = 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 = 78125 \\)
-## Operasi Berpangkat
+# Operasi Berpangkat
+## Perkalian
+Jika sebuah angka berpangkat dikalikan dengan angka berpangkat lainnya, pangkat
+kedua angka tersebut akan ditambah.
+
+\\( a^x \times b^y = (a \times b)^{x + y} \\)
+* \\( 10^4 \times 2^2 = (10 \times 2)^{4 + 2} = 20^6 \\)
+
+## Pembagian
+Jika sebuah angka berpangkat dibagi dengan angka berpangkat lainnya, pangkat
+kedua angka tersebut akan dikurangi.
+
+\\( a^x \div b^y = (a \div b)^{x - y} \\)
+* \\( 10^3 \div 2^4 = (10 \div 2)^{(4 - 2)} = 5^2 = 25 \\)
+
+## Pangkat
+Jika sebuah angka berpangkat dipangkat, pangkatnya akan dikalikan.
+
+\\( (a^x)^y = a^{x \times y} \\)
+* \\( (2^2)^3 = 2^{2 \times 3} = 2^6 = 64 \\)
+
+# Pangkat Istimewa
+Beberapa pangkat merasa mereka lebih baik dari yang lain, dan Matematika setuju
+dengan mereka.
+
+## Pangkat Nol
+If a number is raised to the power of **zero**, the result is **one**.
+Jika sebuah angka dipangkatkan ke **nol**, hasilnya akan selalu **satu**.
+
+\\( a^0 = 1 \\)
+* \\( 5^0 = 1 \\)
+* \\( 69.420^0 = 1 \\)
+
+## Pangkat Negatif
+Jika sebuah angka dipangkatkan dengan angka negatif, juga dikatakan dengan
+bilangan kebalikan, akan sama dengan...
+
+\\( a^{-b} = \dfrac{1}{a^b} \\)
+
+## Pangkat Pecahan
+Akar **Penyebut (y)** dari **bilangan(a)** yang dipangkatkan dengan **Pembilang (x)**.
+
+\\( a^{\frac{x}{y}} = \sqrt[y]{a^x} \\)
+* \\( 5^{\frac{1}{2}} = \sqrt[2]{5} \\)
+* \\( 7^{\frac{2}{3}} = \sqrt[3]{7^2} \\)
+## Persamaan Berpangkat
+1. $$
+\begin{aligned}
+2^{x + 5} &= 64 \\\\
+2^{x + 5} &= 2^6 &\leftarrow\textnormal{ kamu bisa ganti 64 ke bentuk 2 berpangkat (}2^x\textnormal{)} \\\\
+x + 5 &= 6 &\textnormal{eliminasi angka 2nya} \\\\
+x &= 6 - 5 \\\\
+&= 1
+\end{aligned}
+$$
+1. $$
+\begin{aligned}
+16^{x + 2} &= 2^5 \\\\
+(2^4)^{x + 2} &= 2^5 \\\\
+2^{4x + 8} &= 2^5 \\\\
+4x + 8 &= 5 \\\\
+4x &= 5 - 8 \\\\
+4x &= -3 \\\\
+x &= -\dfrac{3}{4}
+\end{aligned}
+$$
diff --git a/lessons/matematika/1-exponents/1.md b/lessons/matematika/1-exponents/1.md
index b8224b2..16bf26b 100644
--- a/lessons/matematika/1-exponents/1.md
+++ b/lessons/matematika/1-exponents/1.md
@@ -7,13 +7,15 @@
# Exponent Operations
## Multiplication
-If an exponented number is multiplied by another exponented number, the exponents would be summed together (instead of being multiplied)
+If an exponented number is multiplied by another exponented number, the
+exponents would be summed together (instead of being multiplied)
\\( a^x \times b^y = (a \times b)^{x + y} \\)
* \\( 10^4 \times 2^2 = (10 \times 2)^{4 + 2} = 20^6 \\)
## Division
-If an exponented number is multiplied by another exponented number, the exponents would be subtracted together (instead of being divided)
+If an exponented number is multiplied by another exponented number, the
+exponents would be subtracted together (instead of being divided)
\\( a^x \div b^y = (a \div b)^{x - y} \\)
* \\( 10^3 \div 2^4 = (10 \div 2)^{(4 - 2)} = 5^2 = 25 \\)
@@ -35,13 +37,36 @@ If a number is raised to the power of **zero**, the result is **one**.
* \\( 69.420^0 = 1 \\)
## Negative Exponent
-If a number is raised to a negative power, also called as an inverse, it would be equal to...
+If a number is raised to a negative power, also called as an inverse, it would
+be equal to...
\\( a^{-b} = \dfrac{1}{a^b} \\)
-
## Fractional Exponent
-
-# Examples
-
-## Exponential Equation
+**Denominator (y)** root of the **number (a)** to the power of the **Numerator (x)**.
+
+\\( a^{\frac{x}{y}} = \sqrt[y]{a^x} \\)
+* \\( 5^{\frac{1}{2}} = \sqrt[2]{5} \\)
+* \\( 7^{\frac{2}{3}} = \sqrt[3]{7^2} \\)
+
+# Exponential Equation
+1. $$
+\begin{aligned}
+2^{x + 5} &= 64 \\\\
+2^{x + 5} &= 2^6 &\leftarrow\textnormal{ you can change 64 into an exponented two (}2^x\textnormal{)} \\\\
+x + 5 &= 6 &\textnormal{eliminate the 2s} \\\\
+x &= 6 - 5 \\\\
+&= 1
+\end{aligned}
+$$
+1. $$
+\begin{aligned}
+16^{x + 2} &= 2^5 \\\\
+(2^4)^{x + 2} &= 2^5 \\\\
+2^{4x + 8} &= 2^5 \\\\
+4x + 8 &= 5 \\\\
+4x &= 5 - 8 \\\\
+4x &= -3 \\\\
+x &= -\dfrac{3}{4}
+\end{aligned}
+$$
diff --git a/lessons/matematika/1-exponents/2-id.md b/lessons/matematika/1-exponents/2-id.md
new file mode 100644
index 0000000..31453a9
--- /dev/null
+++ b/lessons/matematika/1-exponents/2-id.md
@@ -0,0 +1,177 @@
+# Definisi
+Sebuah akar merupakan kebalikan dari pangkat. Sebagai contoh:
+* \\( 4^2 = 16; \sqrt{16} = 4 \\)
+* \\( 5^2 = 25; \sqrt{25} = 5 \\)
+* \\( 3^3 = 27; \sqrt[3]{27} = 3 \\)
+
+# Menyederhanakan Akar Kuadrat
+Kamu dapat menyederhanakan sebuah akar dengan memfaktorkan dengan angka lain
+yang rasional. Dengan kata lain, membagi bilangan akar dengan kuadrat sempurna.
+Setelah itu, akar kuadrat sempurna itu.
+
+Sebagai contoh: **Sederhanakan** \\( \sqrt{60} \\)!
+\\( \sqrt{60} = \sqrt{4 \times 15} = 2\sqrt{15} \\)
+!---(
+#--(
+## 💡 Penjelasan terperinci
+)--#
+1. Kita faktorkan 60. Kita pilih faktor terkecil dengan kuadrat yang sempurna (cont. 4, 9, 16, 25).
+ Kita akan mendapatkan \\(4 \times 15 \\). Untuk membuktikannya, \\( 4
+ \times 15 \\) harus sama dengan 60. Dan itu benar!
+2. Lalu, akar kuadrat sempurnanya, dalam contoh ini, 4.
+ \\( \sqrt{4 \times 15} = 2\sqrt{15} \\)
+)---!
+Contoh lebih banyak:
+* \\( \sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3} \\)
+* \\( \sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5} \\)
+
+!---(
+#--(
+## ❕ Ada akar "sisa"!
+)--#
+Beberapa akar adalah **bilangan tidak rasional**. Bilangan tersebut adalah
+bilangan yang tidak bisa direpresentasikan dengan rasio atau pecahan.
+
+Kita tidak dapat menyederhanakan akar yang tidak rasional. Jadi, akar itu **sudah
+dalam bentuk paling sederhana**.
+)---!
+
+# Operasi Akar
+Pertama-tama, beberapa terminologi!
+1. Koefisien adalah pengali dari akar. Sebagai contoh: \\( 3\sqrt{2} \\); 3 adalah koefisiennya, dan 2 adalah bilangan akarnya.
+
+## Addition
+Root numbers with the same root can be summed together.
+
+\\( a\sqrt{c} + b\sqrt{c} = (a + b)\sqrt{c} \\)
+
+* \\( 3\sqrt{2} + 4\sqrt{2} = (3 + 4)\sqrt{2} = 7\sqrt2 \\)
+* \\( \sqrt5 + 3\sqrt5 = (1 + 3)\sqrt5 = 4\sqrt5 \\)
+
+## Subtraction
+Root numbers with the same root can be subtracted together.
+
+\\( a\sqrt{c} - b\sqrt{c} = (a - b)\sqrt{c} \\)
+
+* \\( 7\sqrt3 - 4\sqrt3 = (7-4)\sqrt3 = 3\sqrt2 \\)
+
+## Multiplication
+Root numbers can be multiplied by any other root numbers.
+
+\\( a\sqrt{c} \times b\sqrt{d} = (a \times b)\sqrt{c \times d} \\)
+
+!---(
+#--(
+## 💡 Tip
+)--#
+If you multiply a root number with another root number that has the same root,
+you can delete the root symbol, aka it becomes a regular number.
+For example:
+
+\\( \sqrt5 \times \sqrt5 = 5 \\)
+
+!---(
+#--(
+### ❓ Why?
+)--#
+Root is the inverse of exponent. If you multiply two numbers together with the
+same value, it is an exponent. If two of them meet together, they will fight
+and both of them dies (they will cancel out), which means it will be a regular
+ol' number.
+
+In this example:
+
+\\( \sqrt5 \times \sqrt5 = \sqrt{5^2} = 5 \\)
+* Here, \\( \sqrt{5} \\) was powered to 2, which cancels it out.
+ * **Why do they cancel out?** We can expand this equation even more.
+ \\( \sqrt5 \times \sqrt5 = \sqrt{5^2} = \sqrt{25} = 5 \\)
+ * \\( \sqrt{25} \\) is equal to 5, so the answer is 5.
+
+---
+
+This also works for every other number.
+
+---
+
+### In conclusion of these tips:
+* If a root is exponented, they will both cancel out. \\( \sqrt[x]{a^x} = a \\)
+ * Because of that, \\( \sqrt{a} \times \sqrt{a} = a \\)
+
+)---!
+)---!
+
+## Division
+Roots can be divided with any other roots.
+
+\\( a\sqrt{c} \div b\sqrt{d} = (a \div b)\sqrt{c \div d} \\)
+
+* \\( 8\sqrt6 \div 4\sqrt3 = (8 \div 4)\sqrt{6 \div 3} = 2\sqrt2 \\)
+
+# Rationalising Roots
+If a fraction has an **irrational** root as the denominator, we should rationalise it.
+
+!---(
+#--(
+## ❓ What? Why?
+)--#
+Usually in mathemathics, a fraction should have a rational number as the
+denominator. If you remember, some roots are **irrational**, like \\( \sqrt2
+\\), \\( \sqrt3 \\), \\( \sqrt 5 \\). They cannot be represented as integers or
+a valid fraction.
+
+You don't have to rationalise a root, but it is widely accepted that the
+denominator is a rational number.
+)---!
+
+Let's learn how to rationalise a root.
+
+## Simple Irrational Fraction
+If you have a simple irrational fraction like this:
+
+\\( \dfrac{1}{\sqrt2} \\)
+
+You can rationalise it by multiplying it with its own denominator. If you
+remember correctly, when you multiply a square root with itself, it will return
+its own number, therefore a rational number!
+
+\\( \dfrac{1}{\sqrt2} \cdot \dfrac{\sqrt2}{\sqrt2} = \sqrt{1\sqrt2}{2} \\)
+
+The value is still (and must be!) the same, rationalising roots are basically
+representing numbers in another way.
+
+### More Examples
+* \\( \dfrac{3}{\sqrt5} \cdot \dfrac{\sqrt5}{\sqrt5} = \dfrac{3\sqrt5}{5} \\)
+* \\( \dfrac{2}{3\sqrt6} \cdot \dfrac{\sqrt6}{\sqrt6} = \dfrac{2\sqrt6}{3 \cdot 6} = \dfrac{2\sqrt6}{18} \\) (you don't need to multiply it with \\( 3\sqrt6\\))
+
+## A little bit more complex fractions
+If you have a fraction like this:
+
+\\( \dfrac{5}{3 + \sqrt2} \\)
+
+You can rationalise it by multiplying it with itself, but invert the signs. Like this:
+
+\\( \dfrac{5}{3 + \sqrt2} \cdot \dfrac{3 - \sqrt2}{3 - \sqrt2} \\)
+\\( \dfrac{5 \cdot (3 - \sqrt2)}{(3 + \sqrt2)(3 - \sqrt2)} \\)
+
+!---(
+#--(
+### ❓ Looks familiar?
+)--#
+If you look closely, \\( (3 + \sqrt2)(3 - \sqrt2) \\) is the same pattern as
+\\( (a + b)(a - b) \\)! This pattern is one of the **special binominal
+products**. We use this a lot in algebra.
+
+So, remember this pattern:
+\\( (a + b)(a - b) = a^2 - b^2 \\)
+)---!
+
+Let's continue.
+
+\\( \dfrac{5 \cdot (3 - \sqrt2)}{(3 + \sqrt2)(3 - \sqrt2)} = \dfrac{5(3 - \sqrt2)}{3^2 - \sqrt{2^2}} \\)
+
+And if you remember correctly, \\( \sqrt{a^2} = a \\). So,
+
+\\( \dfrac{5(3 - \sqrt2)}{3^2 - \sqrt{2^2}} = \dfrac{5(3 - \sqrt2)}{9 - 2}\\)
+\\( = \dfrac{5(3 - \sqrt2)}{6}\\)
+
+And that's how you rationalise complex fractions.
diff --git a/lessons/matematika/1-exponents/2.md b/lessons/matematika/1-exponents/2.md
new file mode 100644
index 0000000..8a15ee3
--- /dev/null
+++ b/lessons/matematika/1-exponents/2.md
@@ -0,0 +1,176 @@
+# Definition
+A root is an inverse of an exponent. For example:
+* \\( 4^2 = 16; \sqrt{16} = 4 \\)
+* \\( 5^2 = 25; \sqrt{25} = 5 \\)
+* \\( 3^3 = 27; \sqrt[3]{27} = 3 \\)
+
+# Simplifying Square Roots
+You can simplify a root by factoring the root number with another number that
+is rational. In other words, divide the root number by the perfect squares.
+After that, root the perfect square.
+
+For example: **Simplify** \\( \sqrt{60} \\)!
+\\( \sqrt{60} = \sqrt{4 \times 15} = 2\sqrt{15} \\)
+!---(
+#--(
+## 💡 Detailed explanation
+)--#
+1. We factorise 60. We choose the smallest factor with a perfect square (e.g. 4, 9, 16, 25).
+ We will get \\(4 \times 15 \\). To verify, \\( 4 \times 15 \\) must be equal to 60. And it is!
+2. Then, root the perfect square, which in this case, is 4.
+ \\( \sqrt{4 \times 15} = 2\sqrt{15} \\)
+)---!
+More examples:
+* \\( \sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3} \\)
+* \\( \sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5} \\)
+
+!---(
+#--(
+## ❕ There are some "leftover" roots!
+)--#
+Some roots are **irrational numbers**. Irrational numbers are numbers that
+cannot be represented by a ratio, aka a fraction.
+
+We cannot simplify the roots that is irrational. So, it is **already in its
+simplest form**.
+)---!
+
+# Root Operations
+Firstly, some terminology!
+1. Coefficient is the multiplier of a root. For example: \\( 3\sqrt{2} \\); 3 is the coefficient here, and 2 is the root.
+
+## Addition
+Root numbers with the same root can be summed together.
+
+\\( a\sqrt{c} + b\sqrt{c} = (a + b)\sqrt{c} \\)
+
+* \\( 3\sqrt{2} + 4\sqrt{2} = (3 + 4)\sqrt{2} = 7\sqrt2 \\)
+* \\( \sqrt5 + 3\sqrt5 = (1 + 3)\sqrt5 = 4\sqrt5 \\)
+
+## Subtraction
+Root numbers with the same root can be subtracted together.
+
+\\( a\sqrt{c} - b\sqrt{c} = (a - b)\sqrt{c} \\)
+
+* \\( 7\sqrt3 - 4\sqrt3 = (7-4)\sqrt3 = 3\sqrt2 \\)
+
+## Multiplication
+Root numbers can be multiplied by any other root numbers.
+
+\\( a\sqrt{c} \times b\sqrt{d} = (a \times b)\sqrt{c \times d} \\)
+
+!---(
+#--(
+## 💡 Tip
+)--#
+If you multiply a root number with another root number that has the same root,
+you can delete the root symbol, aka it becomes a regular number.
+For example:
+
+\\( \sqrt5 \times \sqrt5 = 5 \\)
+
+!---(
+#--(
+### ❓ Why?
+)--#
+Root is the inverse of exponent. If you multiply two numbers together with the
+same value, it is an exponent. If two of them meet together, they will fight
+and both of them dies (they will cancel out), which means it will be a regular
+ol' number.
+
+In this example:
+
+\\( \sqrt5 \times \sqrt5 = \sqrt{5^2} = 5 \\)
+* Here, \\( \sqrt{5} \\) was powered to 2, which cancels it out.
+ * **Why do they cancel out?** We can expand this equation even more.
+ \\( \sqrt5 \times \sqrt5 = \sqrt{5^2} = \sqrt{25} = 5 \\)
+ * \\( \sqrt{25} \\) is equal to 5, so the answer is 5.
+
+---
+
+This also works for every other number.
+
+---
+
+### In conclusion of these tips:
+* If a root is exponented, they will both cancel out. \\( \sqrt[x]{a^x} = a \\)
+ * Because of that, \\( \sqrt{a} \times \sqrt{a} = a \\)
+
+)---!
+)---!
+
+## Division
+Roots can be divided with any other roots.
+
+\\( a\sqrt{c} \div b\sqrt{d} = (a \div b)\sqrt{c \div d} \\)
+
+* \\( 8\sqrt6 \div 4\sqrt3 = (8 \div 4)\sqrt{6 \div 3} = 2\sqrt2 \\)
+
+# Rationalising Roots
+If a fraction has an **irrational** root as the denominator, we should rationalise it.
+
+!---(
+#--(
+## ❓ What? Why?
+)--#
+Usually in mathemathics, a fraction should have a rational number as the
+denominator. If you remember, some roots are **irrational**, like \\( \sqrt2
+\\), \\( \sqrt3 \\), \\( \sqrt 5 \\). They cannot be represented as integers or
+a valid fraction.
+
+You don't have to rationalise a root, but it is widely accepted that the
+denominator is a rational number.
+)---!
+
+Let's learn how to rationalise a root.
+
+## Simple Irrational Fraction
+If you have a simple irrational fraction like this:
+
+\\( \dfrac{1}{\sqrt2} \\)
+
+You can rationalise it by multiplying it with its own denominator. If you
+remember correctly, when you multiply a square root with itself, it will return
+its own number, therefore a rational number!
+
+\\( \dfrac{1}{\sqrt2} \cdot \dfrac{\sqrt2}{\sqrt2} = \sqrt{1\sqrt2}{2} \\)
+
+The value is still (and must be!) the same, rationalising roots are basically
+representing numbers in another way.
+
+### More Examples
+* \\( \dfrac{3}{\sqrt5} \cdot \dfrac{\sqrt5}{\sqrt5} = \dfrac{3\sqrt5}{5} \\)
+* \\( \dfrac{2}{3\sqrt6} \cdot \dfrac{\sqrt6}{\sqrt6} = \dfrac{2\sqrt6}{3 \cdot 6} = \dfrac{2\sqrt6}{18} \\) (you don't need to multiply it with \\( 3\sqrt6\\))
+
+## A little bit more complex fractions
+If you have a fraction like this:
+
+\\( \dfrac{5}{3 + \sqrt2} \\)
+
+You can rationalise it by multiplying it with itself, but invert the signs. Like this:
+
+\\( \dfrac{5}{3 + \sqrt2} \cdot \dfrac{3 - \sqrt2}{3 - \sqrt2} \\)
+\\( \dfrac{5 \cdot (3 - \sqrt2)}{(3 + \sqrt2)(3 - \sqrt2)} \\)
+
+!---(
+#--(
+### ❓ Looks familiar?
+)--#
+If you look closely, \\( (3 + \sqrt2)(3 - \sqrt2) \\) is the same pattern as
+\\( (a + b)(a - b) \\)! This pattern is one of the **special binominal
+products**. We use this a lot in algebra.
+
+So, remember this pattern:
+\\( (a + b)(a - b) = a^2 - b^2 \\)
+)---!
+
+Let's continue.
+
+\\( \dfrac{5 \cdot (3 - \sqrt2)}{(3 + \sqrt2)(3 - \sqrt2)} = \dfrac{5(3 - \sqrt2)}{3^2 - \sqrt{2^2}} \\)
+
+And if you remember correctly, \\( \sqrt{a^2} = a \\). So,
+
+\\( \dfrac{5(3 - \sqrt2)}{3^2 - \sqrt{2^2}} = \dfrac{5(3 - \sqrt2)}{9 - 2}\\)
+\\( = \dfrac{5(3 - \sqrt2)}{6}\\)
+
+And that's how you rationalise complex fractions.
diff --git a/lessons/matematika/1-exponents/3-id.json b/lessons/matematika/1-exponents/3-id.json
new file mode 100644
index 0000000..e69de29
--- /dev/null
+++ b/lessons/matematika/1-exponents/3-id.json
diff --git a/lessons/matematika/1-exponents/3.json b/lessons/matematika/1-exponents/3.json
new file mode 100644
index 0000000..29e0ed3
--- /dev/null
+++ b/lessons/matematika/1-exponents/3.json
@@ -0,0 +1,24 @@
+{
+ "randomised": false,
+ "questionCountForRandomisation": 0,
+ "questions": [
+ {
+ "question": "Is simpliCity a bad game?",
+ "attachment": "",
+ "answers": [
+ {
+ "answer": "Yes",
+ "correct": true
+ },
+ {
+ "answer": "Maybe",
+ "correct": false
+ },
+ {
+ "answer":"No",
+ "correct": false
+ }
+ ]
+ }
+ ]
+}